convert .98L of N20 gas at STP to moles
1 mol of a gas at STP occupies 22.4L
4.375
To convert 0.98 L of N2O gas at STP (Standard Temperature and Pressure) to moles, we need to use the ideal gas law equation, which is:
PV = nRT
Where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
At STP, the conditions are:
Temperature (T) = 273.15 Kelvin
Pressure (P) = 1 atmosphere
So, let's solve the equation for the number of moles (n):
n = PV / RT
Substituting in the given values:
P = 1 atmosphere
V = 0.98 L
R = 0.0821 L·atm/(mol·K)
T = 273.15 Kelvin
n = (1 atm) * (0.98 L) / (0.0821 L·atm/(mol·K)) * (273.15 K)
By performing the calculation, we get:
n ≈ 0.0404 moles
Therefore, 0.98 liters of N2O gas at STP is approximately equal to 0.0404 moles.