A long distance trucker traveled 168 miles in one direction during a snow storm.

The return trip in rainy weather was accomplished at double the speed and took 3 hours less time.
What is the speed going?

since time = distance/speed, if the speed was x,

168/(2x) = 168/x - 3
x = 28

snow storm speed --- x mph

rain storm speed ---- 2x mph

168/x - 168/2x = 3
times 2x
336 - 168 = 6x
x = 168/6 = 28

So he went 28 mph in the snow storm and 56 mph in the rain

check:
snow: 168/28 = 6
rain: 168/56 = 3 , so 3 hours less than in the snow

To find the speed going, we can set up a system of equations based on the given information. Let's assume that the speed going is represented by "x" miles per hour.

Given:
Distance = 168 miles
Speed going = x mph
Speed returning = 2x mph
Time going - Time returning = 3 hours

We can use the formula Time = Distance/Speed to calculate the time.

For the going trip:
Time going = Distance/Speed going = 168/x hours

For the return trip:
Time returning = Distance/Speed returning = 168/(2x) hours

According to the given information, the time going is 3 hours more than the time returning. So we can set up the equation:

Time going - Time returning = 3 hours
168/x - 168/(2x) = 3

To solve this equation, let's find a common denominator:
168(2x) - 168(x) = 3x(2x)
336x - 168x = 6x^2
168x = 6x^2

Divide both sides of the equation by 6x:
28 = x

Therefore, the speed going is 28 miles per hour.