A long distance trucker traveled 168 miles in one direction during a snow storm.
The return trip in rainy weather was accomplished at double the speed and took 3 hours less time.
What is the speed going?
since time = distance/speed, if the speed was x,
168/(2x) = 168/x - 3
x = 28
snow storm speed --- x mph
rain storm speed ---- 2x mph
168/x - 168/2x = 3
times 2x
336 - 168 = 6x
x = 168/6 = 28
So he went 28 mph in the snow storm and 56 mph in the rain
check:
snow: 168/28 = 6
rain: 168/56 = 3 , so 3 hours less than in the snow
To find the speed going, we can set up a system of equations based on the given information. Let's assume that the speed going is represented by "x" miles per hour.
Given:
Distance = 168 miles
Speed going = x mph
Speed returning = 2x mph
Time going - Time returning = 3 hours
We can use the formula Time = Distance/Speed to calculate the time.
For the going trip:
Time going = Distance/Speed going = 168/x hours
For the return trip:
Time returning = Distance/Speed returning = 168/(2x) hours
According to the given information, the time going is 3 hours more than the time returning. So we can set up the equation:
Time going - Time returning = 3 hours
168/x - 168/(2x) = 3
To solve this equation, let's find a common denominator:
168(2x) - 168(x) = 3x(2x)
336x - 168x = 6x^2
168x = 6x^2
Divide both sides of the equation by 6x:
28 = x
Therefore, the speed going is 28 miles per hour.