Can you help me solve for y?
8x-4xy=3
-2x-5y=10
8x - 4xy = 3
8x-3 = 4xy
(8x-3)/4x = y
-2x-5y = 10
5y = -2x-10
y = -(2x+10)/5
Thank you so much
Sure! To solve for y, we can use the method of substitution. Here's how we do it.
First, let's solve the second equation for x:
-2x - 5y = 10
-2x = 10 + 5y
x = (10 + 5y) / -2
Now, substitute this value of x into the first equation:
8x - 4xy = 3
8((10 + 5y) / -2) - 4((10 + 5y) / -2)y = 3
Simplify the equation to solve for y:
-16 - 8y - 20y - 10y² = 6
Combine and rearrange terms:
-10y² - 28y - 16 = 6
Move the constant term to the right side:
-10y² - 28y - 22 = 0
To solve this quadratic equation, you can use the quadratic formula:
y = (-b ± sqrt(b² - 4ac)) / (2a)
Here, a = -10, b = -28, and c = -22. Plug in these values to find the two possible solutions for y.
Once you have the values of y, you can substitute them back into either of the original equations to solve for x.