how many seconds would it takes a boat to accelerate from 13m/s to 20m/s over a distance of 1.25 km ?

V^2 = Vo^2 + 2a*d = 20^2

13^2 + 2a*1250 = 400
2500a = 400-169 = 231
a = 0.0924 m/s^2

t = (V-Vo)/a = (20-13)/0.0924 = 75.8 s.

To determine the time it would take for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km, we can use the equation:

v^2 = u^2 + 2as

Where:
v = final velocity (20 m/s)
u = initial velocity (13 m/s)
a = acceleration (unknown)
s = distance (1.25 km or 1250 m)

Rearranging the equation to solve for acceleration:

a = (v^2 - u^2) / (2s)

Plugging in the values, we get:

a = (20^2 - 13^2) / (2 * 1250)

a = (400 - 169) / 2500

a = 231 / 2500

a ≈ 0.0924 m/s^2

Now, using the equation v = u + at to find the time:

20 = 13 + 0.0924t

6.92 = 0.0924t

t ≈ 74.91 seconds

Therefore, it would take approximately 74.91 seconds for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km.

To find out how long it would take for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km, we need to use the equation of motion:

v^2 = u^2 + 2as

where:
v = final velocity (20 m/s)
u = initial velocity (13 m/s)
a = acceleration (unknown)
s = distance (1.25 km or 1250 m)

First, let's convert the distance from kilometers to meters:

s = 1.25 km = 1250 m

Now we can rearrange the equation to solve for the acceleration:

a = (v^2 - u^2) / (2s)

a = (20^2 - 13^2) / (2 * 1250)

a = (400 - 169) / 2500

a = 231 / 2500

a ≈ 0.0924 m/s^2

Now that we have the acceleration, we can use the equation of motion to find the time it takes:

v = u + at

20 = 13 + (0.0924)t

0.0924t = 20 - 13

0.0924t = 7

t ≈ 75.87 seconds

Therefore, it would take approximately 75.87 seconds for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km.