how many seconds would it takes a boat to accelerate from 13m/s to 20m/s over a distance of 1.25 km ?
V^2 = Vo^2 + 2a*d = 20^2
13^2 + 2a*1250 = 400
2500a = 400-169 = 231
a = 0.0924 m/s^2
t = (V-Vo)/a = (20-13)/0.0924 = 75.8 s.
To determine the time it would take for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km, we can use the equation:
v^2 = u^2 + 2as
Where:
v = final velocity (20 m/s)
u = initial velocity (13 m/s)
a = acceleration (unknown)
s = distance (1.25 km or 1250 m)
Rearranging the equation to solve for acceleration:
a = (v^2 - u^2) / (2s)
Plugging in the values, we get:
a = (20^2 - 13^2) / (2 * 1250)
a = (400 - 169) / 2500
a = 231 / 2500
a ≈ 0.0924 m/s^2
Now, using the equation v = u + at to find the time:
20 = 13 + 0.0924t
6.92 = 0.0924t
t ≈ 74.91 seconds
Therefore, it would take approximately 74.91 seconds for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km.
To find out how long it would take for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km, we need to use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (20 m/s)
u = initial velocity (13 m/s)
a = acceleration (unknown)
s = distance (1.25 km or 1250 m)
First, let's convert the distance from kilometers to meters:
s = 1.25 km = 1250 m
Now we can rearrange the equation to solve for the acceleration:
a = (v^2 - u^2) / (2s)
a = (20^2 - 13^2) / (2 * 1250)
a = (400 - 169) / 2500
a = 231 / 2500
a ≈ 0.0924 m/s^2
Now that we have the acceleration, we can use the equation of motion to find the time it takes:
v = u + at
20 = 13 + (0.0924)t
0.0924t = 20 - 13
0.0924t = 7
t ≈ 75.87 seconds
Therefore, it would take approximately 75.87 seconds for the boat to accelerate from 13 m/s to 20 m/s over a distance of 1.25 km.