The windpipe of a whooping crane is about 1.27 m long. Assuming that the pipe is closed at one end, what is the fundamental frequency of this pipe? Answer in Hz and use 340 m/s for the speed of sound.
To find the fundamental frequency of a closed-end pipe, we can use the formula:
f = v / (4L),
where f is the fundamental frequency, v is the speed of sound, and L is the length of the pipe.
In this case, the length of the windpipe is given as 1.27 m, and the speed of sound is given as 340 m/s. We can substitute these values into the formula to calculate the fundamental frequency:
f = 340 / (4 × 1.27).
Performing the calculations:
f = 340 / 5.08
f ≈ 66.93 Hz.
Therefore, the fundamental frequency of the windpipe of a whooping crane is approximately 66.93 Hz.
To find the fundamental frequency of a closed pipe, we can use the formula:
f = V/4L
Where:
f is the fundamental frequency,
V is the speed of sound, and
L is the length of the windpipe.
Given that the speed of sound is 340 m/s and the length of the windpipe is 1.27 m:
f = 340 / (4 * 1.27)
Calculating this equation, we get:
f ≈ 67.32 Hz
Therefore, the fundamental frequency of the windpipe of a whooping crane is approximately 67.32 Hz.