How do I write the chemical equation for
Copper(II)nitrate + sodium hydroxide -> Copper(II)hydroxide + sodium nitrate?
CuNO3 + NaOH-> CuOH + Na(NO3)
is that right?
Copper(II)hydroxide -> Copper(II)oxide + water
CuOH -> CuO + H2O?
Cu(NO3)2 + 2NaOH --> Cu(OH)2 + 2NaNO3
To write the chemical equation for the given reaction:
Copper(II)nitrate + sodium hydroxide -> Copper(II)hydroxide + sodium nitrate
You need to balance the equation by ensuring that the number of atoms of each element is the same on both sides of the arrow.
First, let's write the correct formulas for each compound:
Copper(II)nitrate: Cu(NO3)2
Sodium hydroxide: NaOH
Copper(II)hydroxide: Cu(OH)2
Sodium nitrate: NaNO3
Now, let's balance the equation step by step:
1. Start with the copper atoms. There is one copper atom on each side of the equation, so we don't need to adjust it.
Cu(NO3)2 + NaOH -> Cu(OH)2 + NaNO3
2. Next, balance the nitrogen atoms. There are two nitrate ions (NO3-) on the left side, so we need two nitrate ions on the right side by adding another NaNO3.
Cu(NO3)2 + 2NaOH -> Cu(OH)2 + 2NaNO3
3. Then, balance the oxygen atoms. On the left side, there are six oxygen atoms (from the two nitrate ions and one water molecule from NaOH). On the right side, there are four oxygen atoms (from two hydroxide ions). To balance the oxygen, we need to add two more water molecules on the right side.
Cu(NO3)2 + 2NaOH -> Cu(OH)2 + 2NaNO3 + 2H2O
Therefore, the correctly balanced chemical equation for the given reaction is:
Cu(NO3)2 + 2NaOH -> Cu(OH)2 + 2NaNO3 + 2H2O
Regarding your second question:
Copper(II)hydroxide -> Copper(II)oxide + water
CuOH -> CuO + H2O
Yes, your equation is correct. Copper(II)hydroxide decomposes to Copper(II)oxide (CuO) and water (H2O).