I don't know how to do this question, or even start it. Please Help. 2 kg copper kettle (specific heat capacity 0.385j/gC) has .0500 kg of water at 20C. How much heat is needed to raise the temperature of the kettle and content to 80C?
total heat needed = heat to raise Cu kettle + heat to raise the water.
total q = [(mass Cu kettle x specific heat Cu x (Tfinal-Tinitial)] + [(mass H2O x specific heat H2O x (Tfinal-Tinitial)]
Solve for total q.
Thank you DrBob222. I really appreciate your help.
171.6 kj
To calculate the amount of heat needed to raise the temperature of the copper kettle and water, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy in joules,
m is the mass in grams,
c is the specific heat capacity in joules/gram·°C, and
ΔT is the change in temperature in °C.
First, let's find the heat energy required to raise the temperature of the copper kettle. The mass of the kettle is given as 2 kg, so we need to convert it to grams:
2 kg = 2000 g
Now we can calculate the heat energy:
Q1 = m * c * ΔT
Q1 = 2000 g * 0.385 J/g·°C * (80°C - 20°C)
Q1 = 2000 g * 0.385 J/g·°C * 60°C
Q1 = 46,200 J
The heat energy required to raise the temperature of the copper kettle is 46,200 J.
Next, let's find the heat energy required to raise the temperature of the water. The mass of the water is given as 0.0500 kg, so we need to convert it to grams:
0.0500 kg = 50.0 g
Now we can calculate the heat energy:
Q2 = m * c * ΔT
Q2 = 50.0 g * 4.18 J/g·°C * (80°C - 20°C)
Q2 = 50.0 g * 4.18 J/g·°C * 60°C
Q2 = 12,540 J
The heat energy required to raise the temperature of the water is 12,540 J.
Finally, we can find the total heat energy required by summing up Q1 and Q2:
Total Q = Q1 + Q2
Total Q = 46,200 J + 12,540 J
Total Q = 58,740 J
So, the total heat energy needed to raise the temperature of the copper kettle and the water to 80°C is 58,740 J.