conver the numeral to a numeral in base 10
1101 basetwo
can some one plz help .
1 * 2^0 = 1
0 * 2^1 = 0
1 * 2^2 = 4
1 * 2^3 = 8
so
13
can you explain more im lost . plz
the first place on the right is either 0 or 1 times 2^0 which is one
just as in base 10
the first place on the right is 0 1,2...9
or one of those numerals times 10^0 which is one
the second place on the right is either 0 or 1 times 2^1 which is 2
just as in base 10
the second place on the right is 0 -- 9 times 10^1 which is ten (the tens place)
third is 2^2 = 4
like 10^2 = 100 the hundreds place
etc
in the tens system 13 = 1*10^1 + 3*10^0
in the two system it is
1*2^3 + 1*2^2 + 0*2^1 + 1*2^0
= 8 + 4 + 0 + 1
Sure, I can help you with that.
To convert a number in base two (binary) to base 10, you need to multiply each digit by the corresponding power of 2 and add them all up.
Let's break down the given number:
1101
Starting from the rightmost digit, the digit in the 0th position is "1". We multiply this digit by 2^0 (which is 1), so we get 1.
Moving to the next digit, in the 1st position, we have "0". Since it's 0, we don't need to consider it in our calculation.
Next, in the 2nd position, we have "1". We multiply this digit by 2^2 (which is 4), so we get 4.
Finally, in the 3rd position, we have "1". We multiply this digit by 2^3 (which is 8), so we get 8.
Now, we add up all the results: 1 + 0 + 4 + 8 = 13.
Therefore, the numeral 1101 in base two is equivalent to the numeral 13 in base 10.