Given the molar concentration of hydroxide ion, calculate the concentration of hydrogen ion. [OH-]=0.0010
Can someone please help me with this process. Thanks
{OH][H] = 10^-14
[H] = 10^-14/10^-3 = 10^-14 * 10^3 = 10^-11
strong base
Given the molar concentration of hydroxide ion, calculate the concentration of hydrogen ion.
Part A
[OH−]=0.0010
Express your answer using two significant figures.
[H+] =
Sure, I can help you with that. To calculate the concentration of hydrogen ion (H+), you can use the concept of Kw, or the ion-product constant of water. Kw is the product of the concentrations of H+ and OH- ions in water and is equal to 1.0 x 10^-14 at 25 degrees Celsius.
The equation for Kw is:
Kw = [H+][OH-]
You are given the molar concentration of hydroxide ion ([OH-]) as 0.0010. Since Kw is a constant, you can solve for the concentration of hydrogen ion ([H+]) using this equation.
To find [H+], rearrange the equation as follows:
[H+] = Kw / [OH-]
Substituting the given value into the equation, we have:
[H+] = (1.0 x 10^-14) / (0.0010)
Calculating this, we can solve for [H+]:
[H+] = 1.0 x 10^-14 / 0.0010
[H+] = 1.0 x 10^-11
Therefore, the concentration of hydrogen ion is 1.0 x 10^-11 mol/L.
Note: In this calculation, we assume that the solution is at 25 degrees Celsius and is neutral. The concentration of H+ and OH- ions will vary depending on the pH of the solution and any other components present.