Ron has $1.35 in dimes and quarters in his pocket. If there are twice how many quarters does he have?
you asked it much better the first time. Why garble the question and post it again?!?!?
Ron will have 10 dimes
To solve this problem, we need to set up an equation based on the information given.
Let's say Ron has 'x' quarters. Since there are twice as many quarters as dimes, Ron must have 2x dimes.
The value of the quarters can be calculated by multiplying the number of quarters (x) by 25 cents (the value of one quarter). So, the value of the quarters is 25x cents.
Similarly, the value of the dimes can be calculated by multiplying the number of dimes (2x) by 10 cents (the value of one dime). So, the value of the dimes is 10 * 2x = 20x cents.
Since the total value of the coins is $1.35, we can set up the equation:
25x + 20x = 135 cents
Combining like terms:
45x = 135 cents
Divide both sides of the equation by 45 to solve for 'x':
x = 135 cents / 45 = 3
So, Ron has 3 quarters.
To check our answer, we can substitute 'x' back into the equation for the value of the quarters and dimes:
Value of quarters = 25 * 3 = 75 cents
Value of dimes = 20 * 3 = 60 cents
Adding the values of quarters and dimes: 75 + 60 = 135 cents ($1.35)
Hence, Ron has 3 quarters.