What mass of rhodium contains as many
atoms as there are zirconium atoms in 23 g of
zirconium?
Multiply 23 grams of zirconium by the molar mass of zirconium, and then by Avogadro's number (6.022x10^23) to get the number of atoms in 23 grams of zirconium.
Then, since we had the grams of zirconium and converted it into atoms of zirconium, we are going to do the reverse process and convert atoms of rhodium to grams of rhodium.
So, take the number of atoms you just found and multiply that by Avogadro's number to get the moles of rhodium, then multiply by rhodium's molar mass to get the mass of rhodium.
If you understand the process, you can take out the steps where you multiply by avogadro's number and instead use the moles of the substances.
I tried what melbell said, except with 56 grams and it didnt work for me. I most likely did it wrong but idk
To determine the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 23 g of zirconium, you need to compare the molar masses of zirconium and rhodium and use Avogadro's number.
1. Find the molar mass of zirconium (Zr) from the periodic table. It is approximately 91.22 g/mol.
2. Calculate the number of moles of zirconium in 23 g using the formula:
Moles = Mass / Molar Mass
Moles = 23 g / 91.22 g/mol
Moles ≈ 0.252 moles
3. Use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol, to find the number of zirconium atoms:
Number of Zr atoms = Moles x Avogadro's number
Number of Zr atoms = 0.252 moles x 6.022 x 10^23 atoms/mol
Number of Zr atoms ≈ 1.518 x 10^23 atoms
4. Now, compare the number of zirconium atoms to the number of rhodium (Rh) atoms. Since we want to find the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 23 g of zirconium, we know that the mass of rhodium will be the same as the mass of zirconium.
5. Find the molar mass of rhodium from the periodic table. It is approximately 102.91 g/mol.
6. Finally, calculate the mass of rhodium using the following formula:
Mass = Moles x Molar Mass
Mass = 0.252 moles x 102.91 g/mol
Mass ≈ 25.97 g
Therefore, the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 23 g of zirconium is approximately 25.97 grams.
To determine the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 23 g of zirconium, we need to follow these steps:
Step 1: Determine the number of zirconium atoms in 23 g of zirconium.
To do this, we need to use the concept of molar mass and Avogadro's number.
1. The molar mass of zirconium (Zr) is approximately 91.22 g/mol. This means that one mole of zirconium weighs 91.22 grams.
2. Since the molar mass of zirconium is 91.22 g/mol, we can calculate the number of moles of zirconium in 23 g using the formula:
Moles = Mass / Molar mass
Moles = 23 g / 91.22 g/mol
Moles ≈ 0.2525 mol
3. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of zirconium atoms.
Number of atoms = Moles x Avogadro's number
Number of atoms = 0.2525 mol x 6.022 x 10^23
Number of atoms ≈ 1.5187 x 10^23 atoms
So, 23 g of zirconium contains approximately 1.5187 x 10^23 zirconium atoms.
Step 2: Determine the molar mass of rhodium (Rh).
The molar mass of rhodium is approximately 102.91 g/mol.
Step 3: Calculate the mass of rhodium containing the same number of atoms as there are zirconium atoms in 23 g of zirconium.
We can use the molar mass of rhodium and the number of zirconium atoms calculated in step 1 to find the mass of rhodium.
1. Calculate the moles of rhodium using Avogadro's number and the number of zirconium atoms:
Moles = Number of atoms / Avogadro's number
Moles = 1.5187 x 10^23 atoms / 6.022 x 10^23
Moles ≈ 0.252 mol
2. Calculate the mass of rhodium using the moles and molar mass of rhodium:
Mass = Moles x Molar mass
Mass = 0.252 mol x 102.91 g/mol
Mass ≈ 25.95 g
Therefore, the mass of rhodium that contains the same number of atoms as there are zirconium atoms in 23 g of zirconium is approximately 25.95 grams.