Hi, have completed a whole worksheet but the challenge involves finding the first five terms from the following terms:
a) 3n^2 - 2
b) 2n^2 - 4
I have no idea how to go about this so any guidance would be greatly appreciated! Thanks
just plug in values for n, from 1 to 5.
Tn is the nth term.
So, for the first one,
T1 = 3(1^2)-2 = 3*1-2 = 3-2 = 1
T2 = 3(2^2)-2 = 3*4-2 = 12-2 = 10
and so on
Would the second be -2, 4, 14, 18 and 46? Thanks
Sure, I can help you with that!
To find the first five terms for a given function, you need to substitute different values of 'n' into the equation and calculate the corresponding 'y' values.
Let's start with the equation: a) 3n^2 - 2
To find the first five terms of this equation, you will substitute values for 'n' starting from 1 going up to 5, and compute the corresponding 'y' values.
For example:
- When n = 1, the equation becomes: 3(1)^2 - 2 = 3 - 2 = 1. So, the first term is 1.
- When n = 2, the equation becomes: 3(2)^2 - 2 = 12 - 2 = 10. So, the second term is 10.
- When n = 3, the equation becomes: 3(3)^2 - 2 = 27 - 2 = 25. So, the third term is 25.
- When n = 4, the equation becomes: 3(4)^2 - 2 = 48 - 2 = 46. So, the fourth term is 46.
- When n = 5, the equation becomes: 3(5)^2 - 2 = 75 - 2 = 73. So, the fifth term is 73.
Therefore, the first five terms for the equation 3n^2 - 2 are: 1, 10, 25, 46, 73.
Similarly, you can follow the same steps to find the first five terms for the equation b) 2n^2 - 4.
I hope this helps you! Let me know if you have any further questions.