Draw the three alkenes, each of formula C5H10, that will form 2-methylbutane upon hydrogenation.

To draw the three alkenes that will form 2-methylbutane upon hydrogenation, you need to first understand the concept of hydrogenation and the structure of alkenes.

Hydrogenation is a chemical reaction in which hydrogen (H2) gas reacts with an unsaturated compound, like an alkene, to convert it into a saturated compound, like an alkane. In this case, we have to start with an alkene that has a formula of C5H10 and hydrogenate it to obtain 2-methylbutane, which has a formula of C5H12.

Now, let's break down the steps to draw the three alkenes:

1. Start with the formula C5H10, which means that there are five carbon atoms (C5) and ten hydrogen atoms (H10).

2. Remember that in an alkene, each carbon atom forms a double bond with another carbon atom. So, the general structure of an alkene with five carbon atoms would be:

H H
| |
H-C=C-C-C-C-H
| |
H H

3. To form 2-methylbutane, we need to add a methyl group (CH3) at the second carbon atom.

H H
| |
H-C-C-C-C-H
| |
CH3

4. Now, to draw the three different alkenes, we need to move the double bond to different positions. Let's start with the first alkene (1-pentene) where the double bond is between the first and second carbon atoms:

H H
| |
C=C-C-C-C-H
| |
CH3

5. For the second alkene (2-pentene), move the double bond between the second and third carbon atoms:

H H
| |
H-C=C-C-C-H
| |
CH3

6. Lastly, for the third alkene (3-pentene), move the double bond between the third and fourth carbon atoms:

H H
| |
H-C-C=C-C-H
| |
CH3

To summarize, the three alkenes (C5H10) that will form 2-methylbutane upon hydrogenation are 1-pentene, 2-pentene, and 3-pentene. They can be represented by the structures mentioned above.