What is the molarity of ZnCl2(aq) that forms when 18.0g of zinc completely reacts with CuCl2(aq) according to the following reaction? (Assume a final volume of 165mL .)
Zn(s)+CuCl2(aq)→ZnCl2(aq)+Cu(s)
mols Zn = grams/atomic mass = ?
mols Zn = mols ZnCl2 since the equation shows 1 mols Zn produces 1 mol ZnCl2.
Then M ZnCl2 = mols/L solution.
To determine the molarity of ZnCl2(aq), you need to follow several steps:
Step 1: Calculate the number of moles of Zn using its molar mass:
The molar mass of zinc (Zn) is 65.38 g/mol. To find the number of moles, divide the given mass by the molar mass:
moles of Zn = mass of Zn / molar mass of Zn
moles of Zn = 18.0 g / 65.38 g/mol
Step 2: Determine the stoichiometry of the reaction:
From the balanced chemical equation, you can see that the reaction ratio between Zn and ZnCl2 is 1:1.
Step 3: Convert moles of Zn to moles of ZnCl2:
Since the reaction ratio is 1:1, the number of moles of ZnCl2 will be the same as the number of moles of Zn.
Step 4: Convert moles to liters:
To convert from moles to liters, you need to use the defined volume. The volume is given as 165 mL, which needs to be converted to liters:
volume = 165 mL * (1 L / 1000 mL)
Step 5: Calculate the molarity of ZnCl2:
Molarity (M) is defined as moles of solute divided by the volume of solution in liters.
molarity of ZnCl2 = moles of ZnCl2 / volume
By following these steps, you can calculate the molarity of ZnCl2(aq).