Calculate the velocity of a skateboarder who accelerates from rest for 6.7 seconds down a ramp at an acceleration of 6.5 m/s2
final velocity=a*t
how do i find a? ^
To calculate the velocity of a skateboarder who accelerates from rest for 6.7 seconds down a ramp at an acceleration of 6.5 m/s^2, we can use the kinematic equation:
V = V0 + at
Where:
V = final velocity
V0 = initial velocity (in this case, the skateboarder starts from rest, so V0 = 0)
a = acceleration
t = time
Plugging in the given values, we have:
V = 0 + (6.5 m/s^2)(6.7 s)
V = 0 + 43.55 m/s
Therefore, the velocity of the skateboarder after 6.7 seconds of accelerating down the ramp is 43.55 m/s.
To calculate the velocity of a skateboarder, you need to use the formula:
v = u + at
where:
v = final velocity
u = initial velocity (in this case, the skateboarder is at rest, so u = 0)
a = acceleration
t = time
Given:
u = 0 (initial velocity)
a = 6.5 m/s^2 (acceleration)
t = 6.7 seconds (time)
Substituting these values into the formula, we get:
v = 0 + (6.5 m/s^2) * (6.7 seconds)
v = 0 + 43.55 m/s
Therefore, the velocity of the skateboarder is 43.55 m/s.