Find the force (in newton) required to lift a mass of 26 kg load with a wheelbarrow (2nd class lever) with the load at 0.75 m from the fulcrum and being lifted at 1.7 m from the fulcrum, assuming ideal conditions.

1.7 x = 26*9.81*.75

To calculate the force required to lift the load with a wheelbarrow using a second-class lever, we can use the principle of torque. Torque is the product of force and distance, and it determines how effectively a lever can lift a load.

In this case, we have a second-class lever, and we need to find the force required to lift a mass of 26 kg. The load is at a distance of 0.75 m from the fulcrum, and we are applying the force to lift the load at a distance of 1.7 m from the fulcrum.

The formula to calculate torque is:

Torque = Force × Distance

In this case, the torque exerted by the load (which is equal to the torque exerted by the force required to lift it) is equal to the torque exerted by the applied force:

Torque(load) = Torque(force)

So, we can set up the equation using the given distances and the unknown force:

26 kg × 9.8 m/s² × 0.75 m = Force × 1.7 m

Here, we assume ideal conditions, which means we consider the load to be a point mass and neglect any friction or other non-ideal factors.

Now, we can solve for the force:

Force = (26 kg × 9.8 m/s² × 0.75 m) / 1.7 m

Force = 27.49 N

Therefore, the force required to lift the 26 kg load with the wheelbarrow is approximately 27.49 Newtons.