What is the value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons?
Fk = u*Fn = 40. Solve for Fn
I'm so confused
Fr tho.. confusing MUCH
To find the value of the normal force, we first need to understand the concept of normal force and its relationship with friction. The normal force is the force exerted by a surface to support the weight of an object resting on it. In most cases, it acts perpendicularly to the surface.
In this case, we are given the coefficient of kinetic friction (μ_k) as 0.22 and the kinetic frictional force (F_k) as 40 newtons. The kinetic frictional force can be calculated using the equation: F_k = μ_k * N, where N is the normal force.
Now, to find the value of the normal force, we rearrange the equation: N = F_k / μ_k
Substituting the given values, we have: N = 40 N / 0.22
Dividing 40 by 0.22, we find: N ≈ 181.82 newtons
Therefore, the value of the normal force is approximately 181.82 newtons.