Can you please tell me if this is a balanced equation for Zinc and acetic acid...
Zn(s) + 2CH3COOH(aq)-->Zn(aq)(CH3COO)2 + H2(g)
I would appreciate any help
One more question - I need a type of element and a type of a compound that are likely to participate in a single replacement reaction.
Would Zinc and Copper be correct?
Thank you
See if the spacing for Zn2+ and CH3COO-2 is a little better.
Zn(s) + 2CH3COOH(aq)-->Zn^2+(aq) + (CH3COO)-2(aq) + H2(g)
Zn is; copper is not a compound. I don't know how to answer the question. Single replacement reactions occur between metals high in the activity series and ions of metals lower in the activity series. For example, Zn metal and Cu(NO3)2 or Zn metal and AgNO3 and hundreds of other examples. But I'm not sure that answers the question since Cu(NO3)2 and AgNO3 are compounds and not types of compounds. You will notice that the Zn + CH3COOH is a single replacement reaction.
Would Hydrocarbons and oxygen be the right answer?
I don't know. Actually I don't understand the question. What choices do you have? That might give me a clue.
To determine if the equation is balanced, you need to ensure that the same number of each type of atom appears on both sides of the equation. Let's go step by step to see if this equation is balanced.
On the left side of the equation:
- Zinc (Zn): There is one atom of zinc.
- Carbon (C): There are zero atoms of carbon.
- Hydrogen (H): There are four atoms of hydrogen.
- Oxygen (O): There are six atoms of oxygen.
On the right side of the equation:
- Zinc (Zn): There is one atom of zinc.
- Carbon (C): There is one atom of carbon.
- Hydrogen (H): There are six atoms of hydrogen.
- Oxygen (O): There are four atoms of oxygen.
As you can see, the number of atoms is not balanced. The equation needs to be adjusted to ensure that the same number of each type of atom appears on both sides.
To balance the equation, we can start by balancing the hydrogen and oxygen atoms. In this case, there are four hydrogen atoms on the left and six on the right, and six oxygen atoms on the left and four on the right.
To balance the hydrogen atoms, we can add a coefficient of 2 in front of the water (H2O) on the right side of the equation:
Zn(s) + 2CH3COOH(aq) --> Zn(aq)(CH3COO)2 + 2H2O(l)
Now there are also four oxygen atoms on both sides of the equation.
Next, let's balance the carbon atoms. There is one carbon atom on the left side and two on the right. To balance it, we add another coefficient of 2 in front of the acetic acid (CH3COOH) on the left side of the equation:
Zn(s) + 2CH3COOH(aq) --> Zn(aq)(CH3COO)2 + 2H2O(l)
Now there is also a balanced number of carbon atoms on both sides.
Finally, let's check the zinc atoms. There is one zinc atom on both sides of the equation, so it is already balanced.
In conclusion, the balanced equation for the reaction between zinc and acetic acid is:
Zn(s) + 2CH3COOH(aq) --> Zn(aq)(CH3COO)2 + 2H2O(l)
Almost but not quite. If you are to write the MOLECULAR equation it should be
Zn(s) + 2CH3COOH(aq)-->Zn(CH3COO)2(aq) + H2(g)
If it is to be an ionic equation it should be
Zn(s) + 2CH3COOH(aq)-->Zn^2+(aq) + (CH3COO)-2(aq) + H2(g)