Write the formula for a complex formed between Zn2 and OH–, with a coordination number of 4.
[Zn(OH)4]^2-
Well, let's see if I can "complex" this question for you! The formula for a complex formed between Zn2 and OH– with a coordination number of 4 is Zn(OH)4. So, it looks like Zn2 got all cuddled up with four OH– friends, forming a cozy complex!
To determine the formula for the complex formed between Zn2+ and OH– with a coordination number of 4, we need to consider the charges of the ions and the coordination preferences of Zn2+.
Zn2+ has a charge of +2, meaning it can accept up to 2 electrons or ligands to form a stable complex. OH–, on the other hand, has a charge of -1.
Since Zn2+ has a coordination number of 4, it can form bonds with 4 ligands. In this case, the OH– ions will act as the ligands.
To balance the charges, we need to combine two OH– ions with one Zn2+ ion. This is because each OH– ion has a charge of -1, and we need two of them to neutralize the charge of the Zn2+ ion, which has a charge of +2.
So, the formula for the complex formed between Zn2+ and OH–, with a coordination number of 4, is [Zn(OH)2]2+.
To write the formula for a complex formed between Zn2+ and OH– with a coordination number of 4, we need to first determine the charge on the complex and the coordination number.
Zn2+ has a charge of 2+ since it loses two electrons to attain a stable configuration. OH– has a charge of 1– since it gains one electron to attain a stable configuration.
The coordination number of 4 indicates that four ligands (in this case, OH– ions) are involved in the complex formation around the central Zn2+ ion.
To form a neutral complex, the total charge of the ligands should balance the charge of the central ion. Zn2+ has a 2+ charge, and since there are four OH– ions, each with a 1– charge, the total charge will be (4) x (1–) = 4–.
To balance the charges, we need two Zn2+ ions to form the complex with four OH– ions. This is because the charge of the Zn2+ ions is 2+ and combining two ions will give us a total charge of (2+ x 2) = 4+.
So, the formula for the complex formed between Zn2+ and OH– with a coordination number of 4 will be [Zn(OH)4]2-.