Which has the greater amount of thermal energy, one liter of water at 50 degrees Celsius or two liters of water at 50 degrees Celsius?
the two liters. becuase theres more energy to be absorbed.
Well, the two liters of water have a "waterfall" more thermal energy than the one liter! Get it? Because there's more water, it's like a bigger splash of thermal energy! So, in this case, two liters would have a greater amount of thermal energy than one liter at the same temperature. It's like having twice the fun at a party, double the water, double the thermal energy!
To determine which has the greater amount of thermal energy, we need to consider both the mass and the temperature of the water.
First, let's calculate the thermal energy of each scenario:
1 liter of water at 50 degrees Celsius:
To calculate the thermal energy of water, we use the specific heat capacity of water, which is approximately 4.18 Joules/gram°C.
The mass of 1 liter of water is approximately 1000 grams (since the density of water is close to 1 g/mL).
The temperature change is 50 degrees Celsius.
Using the formula: Q = mcΔT
where Q is the thermal energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
Q = (1000g) * (4.18 J/g°C) * (50°C)
Q = 209,000 Joules
2 liters of water at 50 degrees Celsius:
Since we have double the amount of water compared to the first scenario, the mass will also be twice as much.
The mass of 2 liters of water is approximately 2000 grams.
Using the same formula as above:
Q = (2000g) * (4.18 J/g°C) * (50°C)
Q = 418,000 Joules
Therefore, two liters of water at 50 degrees Celsius have a greater amount of thermal energy (418,000 Joules) compared to one liter of water at the same temperature (209,000 Joules).
To determine which quantity of water has the greater amount of thermal energy, we can use the formula:
Thermal energy = mass × specific heat capacity × temperature change
In this case, the specific heat capacity of water is approximately 4.18 J/g°C, and we assume that the temperature change is zero since both quantities of water are at the same temperature (50 degrees Celsius).
First, let's calculate the thermal energy of one liter of water at 50 degrees Celsius:
Mass of 1 liter of water = 1000 grams
Temperature change = 0 degrees Celsius (since it's already at 50 degrees Celsius)
Thermal energy of 1 liter of water = 1000 g × 4.18 J/g°C × 0°C = 0 Joules
Now, let's calculate the thermal energy of two liters of water at 50 degrees Celsius:
Mass of 2 liters of water = 2000 grams
Temperature change = 0 degrees Celsius (since it's already at 50 degrees Celsius)
Thermal energy of 2 liters of water = 2000 g × 4.18 J/g°C × 0°C = 0 Joules
As you can see, both quantities of water have the same amount of thermal energy, which is 0 Joules. The thermal energy depends on the mass, specific heat capacity, and temperature difference. In this case, since both quantities have the same temperature, the thermal energy is the same.