Calculate the work done against external atmospheric pressure when 1 g of water changes to
1672cm3
of steam. Take the atmospheric pressure as
1.013×105Nm−2
you could use thus formula:
P=F/A
dW = p A dr
dW = p 4 pi r^2 dr
integrate
W = p (4/3) pi (r final^3 - r initial^3)
W = p (final volume - initial volume)
To calculate the work done against external atmospheric pressure when water changes to steam, we need to use the formula:
Work = Pressure * Change in Volume
Given:
Pressure = 1.013 × 10^5 N/m^2 (atmospheric pressure)
Change in Volume = Final Volume - Initial Volume
To calculate the change in volume, we need to convert the given volume of 1672 cm^3 to m^3:
Change in Volume = (1672 cm^3) * (1 m/100 cm)^3
= 1672 * 10^-6 m^3
Now, we can calculate the work done:
Work = (1.013 × 10^5 N/m^2) * (1672 * 10^-6 m^3)
= 1.693776 Nm
Therefore, the work done against external atmospheric pressure when 1 g of water changes to 1672 cm^3 of steam is approximately 1.693776 Nm.