Using the following data
1. CU3+ + 2e- ---> Cu+ E1= 1.28V
2. CU2+ + e- ---> Cu+ E2= 0.15V
3. Cu2+ + 2e- ----> Cu(s) E3= 0.34V
3. Cu+ + e- ----> Cu (s) E4= 0.52V
calculate the standard reduction potential for the reaction of Cu(III) to Cu(II).
Is it .783 V?
To calculate the standard reduction potential for the reaction of Cu(III) to Cu(II), we need to use a combination of the given reduction potentials (E values) of the individual half-reactions.
The given reduction potentials are as follows:
1. Cu3+ + 2e- → Cu+ E1 = +1.28 V
2. Cu2+ + e- → Cu+ E2 = +0.15 V
3. Cu2+ + 2e- → Cu(s) E3 = +0.34 V
4. Cu+ + e- → Cu(s) E4 = +0.52 V
The reaction we are interested in is the reduction of Cu(III) to Cu(II), which can be written as:
Cu3+ + e- → Cu2+
To determine the reduction potential for this reaction, we can subtract the reduction potential of the oxidation half-reaction (E3) from the reduction potential of the reduction half-reaction (E1).
E = E1 - E3
E = (1.28 V) - (0.34 V)
E = 0.94 V
Therefore, the standard reduction potential for the reaction of Cu(III) to Cu(II) is 0.94 V, not 0.783 V.