Calculate the mass (in grams) of sugar, C12H22O11, in 142.4 mL of a 1.39 M solution of sugar.
(atomic weights: C = 12.01, H = 1.008, O = 16.00)
How many mols do you have? That's M x L = ?
Then mol = grams/molar mass. You have molar mass (or can calculate it) and mols, solve for grams.
Sir, I don't want the answer, I'm having difficulty setting up the problem, once I can figure that out, I will try to solve. Thank you.
And the set up is exactly what I gave you.
Step 1 Calculate the mols you have. That is done by mols = M x L. You have M of 1.39 in the problem and you have L of 0.1424 (in the problem it is 142.4 mL and I've converted that to L).
Step 2.
You know mols = grams/molar mass. mols you have from step 1, molar mass is 180 which I assume you could calculate. That's 6*12.01+12*1.008+6*16 = 180.15 if you want it a little more accurately.
That leaves only one unknown, grams, to calculate.
To calculate the mass of sugar, C12H22O11, in the given solution, we can follow the following steps:
Step 1: Determine the number of moles of sugar in the solution.
To calculate the number of moles, we can use the formula:
moles = concentration (M) × volume (L)
Given:
concentration (M) = 1.39 M
volume in liters (L) = 142.4 mL = 142.4/1000 L = 0.1424 L
Using the formula, we can calculate the number of moles:
moles = 1.39 M × 0.1424 L = 0.198736 moles
Step 2: Calculate the molar mass of C12H22O11.
The molar mass can be found by adding up the atomic masses of all the atoms in the chemical formula.
Molar mass of C12H22O11 = (12.01 × 12) + (1.008 × 22) + (16.00 × 11)
= 144.12 + 22.176 + 176.00
= 342.296 g/mol
Step 3: Calculate the mass of sugar.
To find the mass of sugar, we can use the formula:
mass = moles × molar mass
Using the given values:
mass = 0.198736 moles × 342.296 g/mol
= 67.993 g
Therefore, the mass of sugar, C12H22O11, in 142.4 mL of a 1.39 M solution of sugar is approximately 67.993 grams.