What volume (in milliliters) of 0.496 M aqueous ammonia, NH3, could be made from 17.6 mL of concentrated aqueous ammonia (15.0 M)?
(atomic masses: N = 14.01, H = 1.008)
M1V1 = M2V2
15.0*17.6 = 0.495*mL
(atomic masses: N = 14.01, H = 1.008)
15.0*17.6 = 0.495*mL