the math SAT scores for all students who applied to the school of engineering are normally distributed with M=629 and standard deviation of 60. the school of engineering has decided to accept those students whose scores fall in the top 15%. what is th minimum score an appliant must have in order to be accepted into the engineering school?

An urn contains 9 red,black and 5 white balls.if three balls are drawn one after other without replacement.find the probability that they are red,black and white respectively.

To find the minimum score an applicant must have in order to be accepted into the engineering school, we need to find the z-score that corresponds to the top 15% of the distribution.

First, we need to standardize the score by converting it into a z-score using the formula:

z = (x - μ) / σ

where:
x = the score
μ = the mean of the distribution
σ = the standard deviation of the distribution

In this case, the mean (μ) of the distribution is 629 and the standard deviation (σ) is 60. Let's call the minimum score we are looking for as x.

To find the z-score that corresponds to the top 15%, we need to find the z-value that has an area of 0.15 to its right.

Using a standard normal distribution table or a calculator, we can find that the z-value that corresponds to a right-tail area of 0.15 is approximately 1.036.

Now, we can set up the equation:

1.036 = (x - 629) / 60

Solving for x, we have:

x - 629 = 1.036 * 60

x - 629 = 62.16

x = 629 + 62.16

x ≈ 691.16

Therefore, the minimum score an applicant must have in order to be accepted into the engineering school is approximately 691.16.