if a load 1kg streches a cordby 1.2cm.what is the force constantof the cord?
Force constant= Force/ Extension
= (1×9.8)/ (1/100) N/m
=9.8×100=980N/m
F = m*g = 1*9.8 = 9.8 N
k = F/d = 9.8N/0.012m = 816.7 N/m.
To calculate the force constant of a cord, we need to use Hooke's Law, which states that the force needed to stretch or compress a spring is directly proportional to the displacement. The formula for Hooke's Law is:
F = k * Δx
Where:
F is the force applied to the cord,
k is the force constant (also known as the spring constant), and
Δx is the displacement of the cord.
In this case, the cord stretches by 1.2 cm when a load of 1 kg is applied. We need to convert this displacement to meters to match the unit of force (Newton).
1 cm = 0.01 m
So, Δx = 1.2 cm * 0.01 m/cm = 0.012 meters
Now we can substitute the values into Hooke's Law:
F = k * Δx
1 kg * 9.8 m/s^2 = k * 0.012 meters
Simplifying the equation:
k = (1 kg * 9.8 m/s^2) / 0.012 meters
Therefore, the force constant (or spring constant) of the cord is approximately:
k ≈ 817 N/m