We are two integer brothers apart by 7 on the number line.if you take 5 times of me and add 2 times my brother you'll get 42. Can you find my value?
I believe there are two answer. ... first answer is 5x + 2(x+7)=42 therefore x=4 and 5(8)+2(1)=42
Both answers can be 4 & 11 or 8 &1. Pleade tell me if both are right or not
To solve this problem, we can use algebraic equations. Let's represent the unknown integer value of the first brother as x.
According to the problem, if you take 5 times the first brother's value (5x) and add 2 times the second brother's value (2(x + 7)), you get 42.
So the equation becomes: 5x + 2(x + 7) = 42
We can simplify this equation by distributing the 2 to both terms inside the parentheses:
5x + 2x + 14 = 42
Next, combine like terms:
7x + 14 = 42
To isolate the variable, we subtract 14 from both sides of the equation:
7x + 14 - 14 = 42 - 14
7x = 28
Finally, divide both sides of the equation by 7:
7x/7 = 28/7
x = 4
So the value of the first brother is 4.
Now, let's check if both answers (4 & 11, 8 & 1) are correct.
For the first answer, if the first brother is 4 (x = 4), then the second brother's value would be 4 + 7 = 11.
5 times the first brother would be 5 * 4 = 20, and 2 times the second brother would be 2 * 11 = 22.
If we add them together: 20 + 22 = 42, which matches the given condition. Therefore, the first pair is correct.
For the second answer, if the first brother is 8 (x = 8), then the second brother's value would be 8 + 7 = 15.
5 times the first brother would be 5 * 8 = 40, and 2 times the second brother would be 2 * 15 = 30.
If we add them together: 40 + 30 = 70, which does not match the given condition (42). So, the second pair (8 & 1) is not correct.
Therefore, only the first pair (4 & 11) is the correct answer.