gazelle traveling 200 m/s is launched at a 40 degree angle with respect to the horizontal.
Could you post the whole question?
From what's given, there are lot of questions you can ask from that statement.
To analyse the motion of the gazelle, we can break down its initial velocity into two components: the horizontal component and the vertical component.
The horizontal component represents the velocity in the horizontal direction (along the x-axis), while the vertical component represents the velocity in the vertical direction (along the y-axis).
To find the horizontal component of the velocity (Vx), we can use trigonometry. The horizontal component can be calculated using the formula:
Vx = V * cos(angle)
where V is the magnitude of the initial velocity (200 m/s) and angle is the angle of launch (40 degrees).
Plugging in the values, we have:
Vx = 200 m/s * cos(40 degrees)
To find the vertical component of the velocity (Vy), we can use the same trigonometric formula:
Vy = V * sin(angle)
where V is the magnitude of the initial velocity (200 m/s) and angle is the angle of launch (40 degrees).
Plugging in the values, we have:
Vy = 200 m/s * sin(40 degrees)
The gazelle's velocity components (Vx and Vy) can be used to analyze its motion further, including its trajectory and other related calculations.