Find the equation of the line that passes through the given points
(-8,4) and (2,-1)
y=-1/2x
To find the equation of a line that passes through two given points, you can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope of the line and b is the y-intercept.
First, we need to find the slope (m):
m = (y2 - y1) / (x2 - x1)
Using the coordinates of the two given points (-8,4) and (2,-1), we have:
m = (-1 - 4) / (2 - (-8))
m = -5 / 10
m = -1/2
Now that we have the slope (m), we can substitute it into the slope-intercept form along with one of the given points to find the y-intercept (b).
Using the point (-8,4):
y = mx + b
4 = (-1/2)(-8) + b
4 = 4 + b
b = 4 - 4
b = 0
Therefore, the equation of the line that passes through the given points (-8,4) and (2,-1) is:
y = (-1/2)x + 0 which simplifies to y = -1/2x.