How much energy (in kilojoules) is required to convert 130mL of diethyl ether at its boiling point from liquid to vapor if its density is 0.7138 g/mL?

Use density to convert volume to grams.

Then q = mass ether x heat vaporization. If heat vap is in J then q will be in J and you will need to convert to kJ. You probably can find dHvap in tables in your text or on the web. I don't have these memorized.

To calculate the energy required to convert 130 mL of diethyl ether from liquid to vapor, we need to use the equation:

Energy = mass × heat of vaporization

First, we need to find the mass of diethyl ether using its density.

Mass = volume × density

Mass = 130 mL × 0.7138 g/mL

Mass = 92.894 g

Now, we need to find the heat of vaporization of diethyl ether. The heat of vaporization of diethyl ether is 26.7 kJ/mol.

Since we don't have the moles of diethyl ether, we need to find it using the molar mass. The molar mass of diethyl ether is approximately 74.12 g/mol.

Moles = mass ÷ molar mass

Moles = 92.894 g ÷ 74.12 g/mol

Moles = 1.252 mol

Finally, we can calculate the energy required to convert diethyl ether from liquid to vapor using the equation:

Energy = mass × heat of vaporization

Energy = 92.894 g × (26.7 kJ/mol ÷ 1.252 mol)

Energy = 1981.07 kJ

Therefore, it would require approximately 1981.07 kilojoules of energy to convert 130 mL of diethyl ether from liquid to vapor at its boiling point.

To determine the amount of energy required to convert the given volume of diethyl ether from liquid to vapor, you can utilize the formula:

Energy (in kilojoules) = Mass (in grams) x Heat of Vaporization (in kilojoules per gram)

To calculate the mass of diethyl ether, you can use the density of the substance:

Mass (in grams) = Volume (in mL) x Density (in g/mL)

Let's plug in the values provided:

Volume = 130 mL and Density = 0.7138 g/mL

Mass = 130 mL x 0.7138 g/mL
Mass = 92.594 g (rounded to 3 decimal places)

Now, you need to determine the heat of vaporization of diethyl ether. This value is typically provided in the question or can be found in reference materials. Let's assume the heat of vaporization is 26.0 kilojoules per gram.

Energy = 92.594 g x 26.0 kilojoules/gram
Energy = 2401.244 kilojoules (rounded to 3 decimal places)

Therefore, it would require approximately 2401.244 kilojoules of energy to convert 130 mL of diethyl ether at its boiling point from a liquid to a vapor.