You wish to make a 0.195 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?
mL1 x M1 = mL2 x M2
mL1 x 6.00 = 50.0 mL x 0.195
So you want mL1 of the 6.00 M solution to be placed in a container and add water to a total of 50.0 mL.
1.625ml
To determine the quantity of concentrated acid needed to make a dilute hydrochloric acid solution, we can use the equation C1V1 = C2V2, where C1 and V1 represent the concentration and volume of the concentrated acid solution, and C2 and V2 represent the desired concentration and volume of the dilute solution.
Given:
C1 (concentration of the concentrated acid solution) = 6.00 M
V1 (volume of the concentrated acid solution) = unknown
C2 (desired concentration of the dilute solution) = 0.195 M
V2 (desired volume of the dilute solution) = 50.0 mL
Let's plug in the values into the equation:
C1V1 = C2V2
(6.00 M)(V1) = (0.195 M)(50.0 mL)
Now we can solve for V1, the volume of the concentrated acid solution:
V1 = (0.195 M)(50.0 mL) / 6.00 M
V1 ≈ 1.63 mL
Therefore, you would need to add approximately 1.63 mL of the concentrated hydrochloric acid solution to obtain a total volume of 50.0 mL of the dilute solution with a concentration of 0.195 M.