What is the eq.wt of C7H6O3 and why ??😊
Equivalent weight calculations depend upon the reaction. If you have a reaction it is molar mass/1 if one NaOH is used; it is molar mass/2 if 2 NaOH are used.
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To determine the equivalent weight (eq.wt) of a compound, you need to know the molar mass and the number of equivalents of the compound.
For the given compound C7H6O3, you need to first calculate the molar mass. To do this, you multiply the atomic masses of each element by the number of atoms present and then sum them up.
Carbon (C) has an atomic mass of 12.01 g/mol. As there are 7 carbon atoms, the total mass contribution from carbon is 7 * 12.01 = 84.07 g/mol.
Hydrogen (H) has an atomic mass of 1.01 g/mol. As there are 6 hydrogen atoms, the total mass contribution from hydrogen is 6 * 1.01 = 6.06 g/mol.
Oxygen (O) has an atomic mass of 16.00 g/mol. As there are 3 oxygen atoms, the total mass contribution from oxygen is 3 * 16.00 = 48.00 g/mol.
Adding up the individual contributions, we get:
Total molar mass = 84.07 g/mol + 6.06 g/mol + 48.00 g/mol = 138.13 g/mol
Now, the equivalent weight is defined as the molar mass divided by the number of equivalents. In this case, to determine the number of equivalents, you need additional information. The number of equivalents depends on the specific chemical reaction or context in which the compound is being used. Without that information, it is not possible to determine the equivalent weight accurately.
If you have information about the reaction or context in which C7H6O3 is being used, please provide it, and I will be able to assist you further in determining the equivalent weight.