POINT A AND POINT B ARE 5 UNITS APART .THE COORDINATES OF POINT A ARE (3,-9).THE y COORDINATES OF POINT B IS -9 .WHAT IS A POSSIBLE X-COORDINATE FOR POINT B?
8, -2.
The y coordinate doesn't change, so you just have to add & subtract 5 from 3 in order to get all possible x coordinates without moving from -9.
To find a possible x-coordinate for point B, we can use the fact that A and B are 5 units apart. Since the y-coordinate of point B is -9, it means that both points A and B lie on a horizontal line with a y-coordinate of -9.
Given that the x-coordinate of point A is 3, we can calculate the possible x-coordinate for point B using the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Since the y-coordinates of both points are the same, we only need to consider the difference between the x-coordinates.
(3 - x)^2 = 5^2
Simplifying the equation gives:
9 - 6x + x^2 = 25
Rearranging the equation further:
x^2 - 6x - 16 = 0
Now we can solve this quadratic equation to find the possible x-coordinate for point B.
Using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
where a = 1, b = -6, and c = -16, we can substitute these values into the formula:
x = (-(-6) ± √((-6)^2 - 4(1)(-16))) / (2(1))
Simplifying further:
x = (6 ± √(36 + 64)) / 2
x = (6 ± √100) / 2
x = (6 ± 10) / 2
This gives us two possible solutions for the x-coordinate of point B:
x1 = (6 + 10) / 2 = 16 / 2 = 8
x2 = (6 - 10) / 2 = -4 / 2 = -2
Therefore, a possible x-coordinate for point B can be either 8 or -2.
To find the possible x-coordinate for point B, we know that point A is 5 units apart from point B and the y-coordinate of point B is -9. We also know that the x-coordinate of point A is 3.
To find the possible x-coordinate for point B, we can use the distance formula, which states that the distance between two points (x1, y1) and (x2, y2) is given by:
distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, the distance between point A and B is 5 units. Plugging in the given values:
5 = sqrt((x - 3)^2 + (-9 - (-9))^2)
Simplifying, we get:
25 = (x - 3)^2
Taking the square root of both sides, we have two possible cases:
1. x - 3 = √25 = 5
Solving for x, we get x = 5 + 3 = 8
2. x - 3 = -√25 = -5
Solving for x, we get x = -5 + 3 = -2
Therefore, the possible x-coordinates for point B are 8 and -2.