A plane leaves an airport X, 20.6degrees east and 36.8 north degrees and flies due south along the same longitude for 8 hours at the rate of 1000km/h to another airport Y, 20.6degrees east and tita degree south. The plane then flies west to another airport Z for 8hours at the same speed. Calculate, to the nearest degree: a. The value of tita (b). The logitude of Z
Is there no other ans
Not clear
The radius of earth is 6371 km
We have rθ = 8000, so
θ = 8000/6371 = 71.9°
Y is at 20.6°E 35.1°S
Now, at latitude Ø, the radius of the circle of latitude is r' = r cosØ
So, r' = 6371 cos 35.1° = 5210 km
At that latitude, 8000km is 88.0°
Z is at 67.4°W 35.1°S
Z is thus at
To calculate the value of tita and the longitude of Z, we need to determine the distance traveled in the southward direction and the distance traveled in the westward direction.
First, let's calculate the distance traveled in the southward direction (airport Y).
Distance = Speed * Time
Distance = 1000 km/h * 8 hours
Therefore, the distance traveled in the southward direction is 8000 km.
Now, let's determine the value of tita.
We know that the plane started at 36.8 degrees north and traveled a distance of 8000 km in the southward direction. We also know that the latitude decreases by 1 degree for every 111 km traveled in the southward direction.
So, tita = 36.8 - (8000 / 111)
Now, let's calculate the longitude of airport Z.
Since the plane flew due south along the same longitude, the longitude remains the same. So, the longitude of Z is also 20.6 degrees east.
Therefore, to the nearest degree:
(a) The value of tita is 29 degrees.
(b) The longitude of Z is 21 degrees east.