The drawing shows two transverse waves traveling on two strings. The linear density of each string is 0.0483 kg/m, and the tension is provided by a 15.0-N block that is hanging from the string. Determine the speed of the wave in part (a) and part (b) of the drawing.
To determine the speed of the wave in part (a) and part (b) of the drawing, we can use the wave speed formula, which is given by:
v = √(F/T),
where:
- v is the wave speed,
- F is the tension acting on the string, and
- T is the linear density of the string.
In part (a) of the drawing:
- The tension acting on the string is provided by a 15.0-N block.
- The linear density of the string is 0.0483 kg/m.
Substituting the values into the formula, we have:
v = √(15.0 N / 0.0483 kg/m).
To calculate the wave speed, divide the tension by the linear density:
v = √(310.37 m^2/s^2).
Therefore, in part (a) of the drawing, the speed of the wave is approximately 17.6 m/s.
In part (b) of the drawing, the same calculations can be applied to find the wave speed using the given tension and linear density.
Note: Ensure that all units are consistent throughout the calculations.