A cord 0.65m long exerts a centripetal force of 23N on a whirling 2kg mass tied to the end of the cord. What is the velocity of the whirling mass? Round to nearest tenth.
For this problem, I used to formula V = square root of f/rm.
I did the square root of 23/0.65(2) = 8.4m/s^2, but it wasn't correct.
Thanks for your help!
To find the velocity of the whirling mass, we can use the formula for centripetal force:
F = (mv^2) / r
Where:
F is the centripetal force (23N)
m is the mass of the object (2kg)
v is the velocity of the object (unknown)
r is the radius (0.65m)
Rearranging the formula, we get:
v^2 = (Fr) / m
Now we can plug in the values:
v^2 = (23 N * 0.65 m) / 2 kg
v^2 = 14.95 m^2/s^2
Finally, we take the square root of both sides to find the velocity:
v = √(14.95) ≈ 3.9 m/s
Therefore, the velocity of the whirling mass is approximately 3.9 m/s.