How much heat is required to warm 1.60kg of sand from 22.0∘C to 100.0∘C? The heat capacity of sand is 0.84 J⋅g−1⋅K−1

q = mass sand x specific heat sand x (Tfinal-Tinitial)

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To calculate the amount of heat required to warm the sand, you can use the formula:

Q = m * C * ΔT

Where:
Q is the heat energy in Joules
m is the mass of the sand in grams (1.60 kg = 1600 g)
C is the specific heat capacity of sand in J⋅g^(-1)⋅K^(-1) (0.84 J⋅g^(-1)⋅K^(-1))
ΔT is the change in temperature in Kelvin (100.0°C - 22.0°C = 78.0°C)

First, convert the mass from kilograms to grams:
m = 1.60 kg * 1000 g/kg = 1600 g

Next, convert the change in temperature from Celsius to Kelvin:
ΔT = 100.0°C - 22.0°C = 78.0 K

Now, plug the values into the formula:

Q = 1600 g * 0.84 J⋅g^(-1)⋅K^(-1) * 78.0 K

Calculating this expression:

Q = 1600 * 0.84 * 78 = 99,072 Joules

Therefore, 99,072 Joules of heat are required to warm 1.60 kg of sand from 22.0°C to 100.0°C.