What are the products for KMnO4 + FeSO4 + NaOH? What is the net ionic equation? I am pretty sure one of the products in MnO2, because I got a muddy brown parcipitate, but I've been getting a variety of answers.
Fe^2+ goes to Fe^3+
MnO4^- goes to MnO2 in basic solution (which this is with NaOH)
Very useful
excellent answer thanks
To determine the products of a chemical reaction, such as the one involving KMnO4, FeSO4, and NaOH, we need to follow some steps:
Step 1: Write out the balanced chemical equation.
The given reactants are KMnO4, FeSO4, and NaOH. The balanced chemical equation for this reaction is:
2 KMnO4 + 10 FeSO4 + 8 NaOH -> 2 K2SO4 + 2 MnO2 + 5 Fe(OH)2 + 3 Na2SO4 + 3 H2O
Step 2: Identify the spectator ions.
Next, we identify the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the chemical reaction. In this case, the spectator ions are K+ and SO4^2-.
Step 3: Write the net ionic equation.
To write the net ionic equation, we remove the spectator ions from the balanced chemical equation. In this case, we remove the spectator ions K+ and SO4^2-. Thus, the net ionic equation for this reaction is:
2 MnO4- + 10 Fe2+ + 8 OH- -> 2 MnO2 + 5 Fe(OH)2
Based on this net ionic equation, we can see that one of the products indeed is MnO2, which is a muddy brown precipitate.
It's worth noting that the actual products may vary depending on the reaction conditions, concentrations, and other factors. It's always a good idea to confirm the observations with other sources or experiments.