A person is pulled to the right on a sled (total mass of 60.1 kg) across the surface of a frozen pond with a force of 62.9 Newtons so that they move with a constant velocity. What is the force of friction acting on the sled? Choose your coordinate system so that upward, and to the right are each positive values.
Fap-Fk = m*a = m*0 = 0
Fk = Fap = 62.9 N. = Force of kinetic
friction.
To determine the force of friction acting on the sled, we can use Newton's first law of motion, also known as the law of inertia. According to this law, if an object is moving with a constant velocity, the net force acting on it must be zero.
In this scenario, the person is pulled to the right with a force of 62.9 N. Since the velocity is constant, the net force on the person-sled system must be zero. Therefore, the force of friction acting on the sled would be equal in magnitude, but opposite in direction to the pulling force.
Let's break down the forces acting on the sled:
1. The pulling force to the right: 62.9 N
2. The force of friction (unknown) to the left: -Ffriction
Since the sled is moving with constant velocity, the forces in the horizontal direction must balance out. Therefore, we can set up the following equation:
62.9 N - Ffriction = 0
To find the force of friction, we can rearrange the equation:
Ffriction = 62.9 N
Therefore, the force of friction acting on the sled is 62.9 N.