a car accidently roll off a cliff. as it leaves the cliff it has a horizontal velocity of 13m/s.it hits the ground 60m from the shoreline. calculate the height of cliff.
Xo = 13 m/s.
Dx = 60 m.
h = ?
Dx = Xo * Tf = 60
Tf = 60/Xo = 60/13 = 4.62 s. = Fall time.
h = 0.5g*Tf^2 = 4.9*4.62^2 = 105 m.
thank you
h=1/2 gt^2=105m
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grade 10 answer acare accidenty off acliff. as it leaves the cliff it has a horizontal velocity of 13m/s, it hits the ground 60 m from the shoreline. calculate the height of the cliff.
105m
Given required solution X=60m
g=9.8m/s^2 h=? X=Vox.t
Vox=13m/s t=X/vox
t= 60m/13m/s
t=4.62sec
Then now, h=1/2gt^2=0.5*9.8*21.34=104.56m=105m