110 members of a sports club play atleast one of the games, football, basketball and volleyball. If 20 play football and basketball only, 15 play football and volleyball only, 26 play basketball and volleyball only, x play all the three games, 2x each play only one game, how many play basketball altogether?

Let the Sports Club be denoted by U,

.
F = Football
.
B = Basketball
.
V = Volleyball
.
n(U) = 110
.
n(FnBnC') = 20
.
n(FnVnB') = 15
.
n(BnVnF') = 26
.
n(FnBnV) = x
.
n(FnB'nV') = n(F'nBnV') = (F'nB'nV) = 2x
.

Note: B', F' and V' denote the complements of the various sets(clubs).
.
n(U) = n(FuBuV) + n(FuBuV)'
.
In this case, n(FuBuV)' is empty.
.
110 = 2x + 20 + x + 15 + 2x + 26 + 2x
.
110 = 61 + 7x
.
49 = 7x
.
x = 7
.
n(B) = 20 + 26 + x + 2x
.
n(B) = 20 + 26 + 3x
.
n(B) = 20 + 26 + 21
.
n(B) = 67
.
67 members play Basketball altogether.

~Darematics(07034495462)

Pls Ayodeji And Edidiong Umanah How Did U Get 52 To Be The Answer

i need answer

52 is the answer

52

Pls how was the answer 52 gotten

67 members play basketball altogether

How many played football and how many played volleyball. Please I need a straight answer

pls how did you get 52

Pls how was 52 gotten