H3PO4+3Ca(OH)2=Ca3(PO4)2=6H2O
If 44.6g of Ca3(PO4)2 are formed in the above reaction, how many moles of H3PO4 must have been consumed?
First, balance the equation. It isn't balanced now.
mols Ca3(PO4)2 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols Ca3(PO4)2 to mols H3PO4.
To find the number of moles of H3PO4 consumed, we need to use the balanced chemical equation:
H3PO4 + 3Ca(OH)2 → Ca3(PO4)2 + 6H2O
From the equation, we can see that 1 mole of H3PO4 reacts with 1 mole of Ca3(PO4)2. Therefore, the number of moles of H3PO4 can be calculated using the molar mass of Ca3(PO4)2 and the given mass of Ca3(PO4)2.
The molar mass of Ca3(PO4)2 can be calculated as follows:
1 atom of Phosphorus (P) = 30.97 g/mol
4 atoms of Oxygen (O) = 4 × 16.00 g/mol = 64.00 g/mol
2 atoms of Calcium (Ca) = 2 × 40.08 g/mol = 80.16 g/mol
Adding these up, we get:
Molar mass of Ca3(PO4)2 = 30.97 g/mol + 64.00 g/mol + 64.00 g/mol + 80.16 g/mol = 239.13 g/mol
Now we can calculate the number of moles of Ca3(PO4)2 using the given mass of 44.6 g:
Number of moles = mass / molar mass
Number of moles = 44.6 g / 239.13 g/mol = 0.1866 mol
Since the stoichiometric ratio between H3PO4 and Ca3(PO4)2 is 1:1, the same amount of moles of H3PO4 would have been consumed.
Therefore, 0.1866 moles of H3PO4 must have been consumed in the reaction.
To find the number of moles of H3PO4 consumed, we first need to determine the molar mass of Ca3(PO4)2 and then use stoichiometry to convert grams of Ca3(PO4)2 to moles of H3PO4.
1. Calculate the molar mass of Ca3(PO4)2:
- The molar mass of Ca is approximately 40.08 g/mol.
- The molar mass of P is approximately 30.97 g/mol.
- The molar mass of O is approximately 16.00 g/mol.
Therefore, the molar mass of Ca3(PO4)2 is:
(3 * 40.08) + (2 * (30.97 + (4 * 16.00))) = 310.18 g/mol.
2. Use the equation balanced equation to set up a stoichiometric conversion:
From the balanced equation:
1 mol H3PO4 : 1 mol Ca3(PO4)2
X mol H3PO4 : 44.6 g Ca3(PO4)2
3. Convert grams of Ca3(PO4)2 to moles using its molar mass:
Moles of Ca3(PO4)2 = (mass / molar mass)
Moles of Ca3(PO4)2 = (44.6 g / 310.18 g/mol)
4. Calculate the number of moles of H3PO4 consumed using the stoichiometric ratio:
Moles of H3PO4 = (moles of Ca3(PO4)2 * ratio of H3PO4 to Ca3(PO4)2)
Moles of H3PO4 = (44.6 g / 310.18 g/mol) * (1 mol H3PO4 / 1 mol Ca3(PO4)2)
Therefore, the number of moles of H3PO4 consumed would be the result of the above calculation.