Sonia has 3 bracelets. She wears them all at the same time but in different order each day. How many different bracelet combinations does sonia have to choose from.
3x2x1 = 6 different ways
27
To find the number of different bracelet combinations Sonia has to choose from, we can use the concept of permutations.
Since Sonia has 3 bracelets and wears them all at the same time, the number of different combinations is the same as finding the total number of permutations of 3 objects taken 3 at a time.
The formula for permutations is given by: P(n, r) = n! / (n - r)!
In this case, n = 3 (number of bracelets) and r = 3 (number of bracelets chosen).
P(3, 3) = 3! / (3 - 3)! = 3! / 0! = 3! = 3 x 2 x 1 = 6
Therefore, Sonia has a total of 6 different bracelet combinations to choose from.