A toy car in the figure below runs off the edge of a table that is h = 1.175 m high. The car lands d = 0.400 m from the base of the table .How long did it take the car to fall? How fast was the car going on the table?
A car starts from rest and travels with a constant acceleration at a distance of 500 meters.find its velocity at after 30secs. Express your answer in miles/hr in scientific notation?
A car starts from rest and travels with a constant acceleration at a distance of 500 meters.find its velocity at after 30secs. Express your answer in miles/hr in scientific notation?
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To find the time it took for the car to fall, we can use the equation of motion for vertical free fall:
h = (1/2)gt^2
Where:
- h is the height (1.175 m),
- g is the acceleration due to gravity (9.8 m/s^2),
- t is the time.
To find the time, we rearrange the equation:
t = sqrt((2h) / g)
Substituting the given values:
t = sqrt((2 * 1.175) / 9.8)
t ≈ 0.485 seconds
So, it took approximately 0.485 seconds for the car to fall.
To find the initial velocity of the car on the table, we need to use the equation of motion for horizontal motion:
d = vt
Where:
- d is the distance (0.400 m),
- v is the initial velocity of the car,
- t is the time.
Rearranging the equation gives:
v = d / t
Substituting the given values:
v = 0.400 / 0.485
v ≈ 0.825 m/s
Therefore, the car was going approximately 0.825 m/s on the table.