Two toy ducks attached to each other by a string, are being pulled by a child. The front duck is m1= 5.0 kg and the back duck is m2= 2.0 kg. The happy guy pulls them with a force of 10 N and friction exists. The toys are moving with constant velocity.
A) if the coefficient of kinetic friction is = 0.12, find the force of friction which is acting on the second duck.
B) calculate the tension in the string connecting the ducks
I don't know how to start these 2 questions..
I have the answers but i don't know if i am right
A) 2.4
To solve these two questions, we need to consider the forces acting on the toy ducks and use Newton's second law of motion.
A) To find the force of friction acting on the second duck, we first need to find the force of friction acting on the first duck. Since the toys are moving with constant velocity, it means the net force acting on the system is zero. Therefore, the force of friction acting on the first duck must be equal to the force applied by the child.
1. Find the force of friction on the first duck:
Net force = Force applied - Force of friction on the first duck
0 = 10 N - Force of friction on the first duck
2. Now, we can find the force of friction on the first duck:
Force of friction on the first duck = Force applied
Force of friction on the first duck = 10 N
3. Since the toys are connected by a string, the force of friction on the first duck is also equal to the force of friction on the second duck.
4. Therefore, the force of friction on the second duck is also 10 N.
B) To calculate the tension in the string connecting the ducks, we need to consider the forces acting on the second duck:
1. The tension in the string is pulling the second duck forward with the same force that the friction is trying to pull it backward.
2. So, the tension in the string is equal to the force of friction on the second duck.
3. Therefore, the tension in the string connecting the ducks is 10 N.