Two dynamics carts are placed end to end. Cart 1 (1.2 kg) is stuck to cart 2 (1.8 kg). Cart 1 is pushed with a force of 18.9 N (west),causing cart 1 to push cart 2 forward. Ignore the force of friction.

Calculate the acceleration of each cart
Calculate the force that cart 1 exerts on cart 2

Well, well, well, we've got ourselves a physics problem! Let's get down to business and calculate away!

To find the acceleration of each cart, we'll need to use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration.

For cart 1:
The net force acting on cart 1 is the force pushing it forward (18.9 N).
The mass of cart 1 is 1.2 kg.
So, we can say that 18.9 N = (1.2 kg) * a1, where a1 is the acceleration of cart 1.
Solving for a1, we find that a1 = 18.9 N / 1.2 kg ≈ 15.75 m/s².

For cart 2:
Since cart 1 is pushing cart 2 forward, the net force acting on cart 2 is the same as the force applied to cart 1 (18.9 N).
The mass of cart 2 is 1.8 kg.
Using Newton's second law again, we can say that 18.9 N = (1.8 kg) * a2, where a2 is the acceleration of cart 2.
Solving for a2, we find that a2 = 18.9 N / 1.8 kg ≈ 10.5 m/s².

Now, to calculate the force that cart 1 exerts on cart 2, we know that the force acting on cart 2 is due to the interaction with cart 1 (Newton's third law, baby!).
So, the force that cart 1 exerts on cart 2 is equal in magnitude but opposite in direction to the force applied to cart 1, which is 18.9 N (west). Thus, the force that cart 1 exerts on cart 2 is 18.9 N (east).

Voila! We've got our answers. Now, that wasn't too scary, was it?

To calculate the acceleration of each cart, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

Let's start by calculating the net force acting on both carts:

The force applied to cart 1 (F1) is 18.9 N (west), and there is no external force acting on cart 2, so the net force acting on cart 1 (FNet1) is equal to the force applied to it:

FNet1 = F1 = 18.9 N (west)

Since cart 1 and cart 2 are stuck together, the net force acting on cart 2 (FNet2) is the force that cart 1 exerts on cart 2 (F2-1):

FNet2 = F2-1

To calculate the force that cart 1 exerts on cart 2, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. Therefore:

F2-1 = -F1

Now we can substitute F1 into the equation:

F2-1 = -(18.9 N)

Next, we can calculate the acceleration of each cart:

For cart 1 (a1):

FNet1 = m1 * a1

a1 = FNet1 / m1

Substituting the values we know:

a1 = (18.9 N) / (1.2 kg)

a1 ≈ 15.8 m/s^2 (west)

For cart 2 (a2):

FNet2 = m2 * a2

Since FNet2 = F2-1, we can substitute the value we calculated for F2-1 into the equation:

-(18.9 N) = (1.8 kg) * a2

a2 = -(18.9 N) / (1.8 kg)

a2 ≈ -10.5 m/s^2 (west)

So, the acceleration of cart 1 is approximately 15.8 m/s^2 (west), and the acceleration of cart 2 is approximately -10.5 m/s^2 (west).

Please note that the negative sign indicates that cart 2 is accelerating in the opposite direction (west) to cart 1.

To calculate the acceleration of each cart, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, we need to find the net force acting on each cart and divide it by the respective masses.

1. To find the net force on Cart 1, we need to subtract the force exerted by Cart 2 on Cart 1. Since there is no friction involved, the only force acting on Cart 1 is the force applied to it, which is 18.9 N. Therefore, the net force on Cart 1 is 18.9 N.

2. For Cart 2, since there is no external force acting on it except the force exerted by Cart 1, the net force on Cart 2 is equal to the force exerted by Cart 1, which is 18.9 N.

Now, we can calculate the acceleration of each cart:

3. Acceleration of Cart 1: Using Newton's second law, the acceleration of Cart 1 is given by the net force on Cart 1 divided by its mass. The mass of Cart 1 is 1.2 kg. Therefore, the acceleration of Cart 1 is 18.9 N / 1.2 kg = 15.75 m/s² (west).

4. Acceleration of Cart 2: Similarly, the acceleration of Cart 2 is given by the net force on Cart 2 divided by its mass. The mass of Cart 2 is 1.8 kg. Therefore, the acceleration of Cart 2 is 18.9 N / 1.8 kg = 10.5 m/s² (west).

To calculate the force that Cart 1 exerts on Cart 2, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. Since Cart 2 exerts a force on Cart 1, Cart 1 will exert an equal and opposite force on Cart 2.

Therefore, the force that Cart 1 exerts on Cart 2 is also 18.9 N (east).

force=total mass* acceleration=sumMasses*a

calculate a
force on cart2=mass2*a

How would i find the acceleration?