How many moles of magnesium are needed to react with 16 g of O2?
2 MgO (s) + O2 (g) → 2 MgO (s)
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To determine the number of moles of magnesium (Mg) needed to react with 16 g of oxygen (O2), you need to follow these steps:
1. Determine the molar mass of O2: Oxygen (O) has a molar mass of approximately 16 g/mol. Since O2 is a diatomic molecule, its molar mass is twice that, which is 32 g/mol.
2. Calculate the number of moles of O2: Divide the given mass of O2 (16 g) by its molar mass (32 g/mol). The grams unit cancels out, leaving you with the number of moles.
Moles of O2 = (16 g) / (32 g/mol) = 0.5 mol
3. Use the balanced equation to relate the number of moles of O2 to the number of moles of Mg:
According to the equation, 2 moles of Mg react with 1 mole of O2. Therefore, the mole ratio of Mg to O2 is 2:1.
Since we have 0.5 moles of O2, we can calculate the moles of Mg using the mole ratio.
Moles of Mg = 0.5 mol O2 × (2 mol Mg / 1 mol O2) = 1 mol Mg
Therefore, 1 mole of magnesium is required to react with 16 g of O2.