Determine the number of grams of oxygen in 13 grams of calcium acetate.
3.29g Ca
To determine the number of grams of oxygen in 13 grams of calcium acetate, we first need to know the molecular formula of calcium acetate which is Ca(C2H3O2)2.
Next, we can calculate the molar mass of calcium acetate. The molar mass of calcium (Ca) is 40.08 g/mol, the molar mass of carbon (C) is 12.01 g/mol, the molar mass of hydrogen (H) is 1.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Since there are two carbon atoms, four hydrogen atoms, and four oxygen atoms in calcium acetate, we can calculate its molar mass as follows:
(1 * 40.08 g/mol) + (2 * 12.01 g/mol) + (4 * 1.01 g/mol) + (4 * 16.00 g/mol) = 158.17 g/mol
Now we can calculate the mass of oxygen in 13 grams of calcium acetate.
First, we need to determine the molar ratio of oxygen to calcium acetate by dividing the molar mass of oxygen by the molar mass of calcium acetate:
(4 * 16.00 g/mol) / 158.17 g/mol = 0.4034
This means that for every 1 mole of calcium acetate, there are 0.4034 moles of oxygen.
To calculate the mass of oxygen in 13 grams of calcium acetate, we multiply the mass of calcium acetate by the molar ratio:
13 g * 0.4034 = 5.253 g
Therefore, there are approximately 5.253 grams of oxygen in 13 grams of calcium acetate.