what force is applied by Andre if he does 250 J of work as he pushes a box 19 M along the ground ?
To find the force applied by Andre, we can use the work-energy principle. The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.
The formula for work is:
Work = Force × Distance × Cosθ
Where:
- Work is measured in joules (J)
- Force is the applied force (what we want to find)
- Distance is the displacement in meters (m)
- Cosθ is the angle between the force direction and the direction of displacement (assuming the force is applied in the same direction as the displacement, the angle will be 0, so cos(0) = 1)
Given:
- Work = 250 J
- Distance = 19 m
- Cosθ = 1 (assuming the force is applied in the same direction as the displacement)
We can rearrange the formula to solve for force:
Force = Work / (Distance × Cosθ)
Plugging in the given values:
Force = 250 J / (19 m × 1)
Force ≈ 13.16 N
Therefore, the force applied by Andre is approximately 13.16 Newtons.
Work = F*d = 250 J.
F = 250/d = 250/19 = 13,16 N.