7. The specific heat of wood is 2.03 J/g∙°C. How much heat is needed to convert 550. g of wood at -15.0°C to 10.0°C?
To calculate the heat required to convert the wood from -15.0°C to 10.0°C, we can use the formula:
Q = m × c × ΔT
Where:
Q = heat (in joules)
m = mass of the wood (in grams)
c = specific heat capacity of wood (in J/g∙°C)
ΔT = change in temperature (in °C)
Given:
m = 550. g
c = 2.03 J/g∙°C
ΔT = (10.0°C - (-15.0°C))
ΔT = (10.0 + 15.0)°C
ΔT = 25.0°C
Now we can substitute the values into the formula and calculate the heat:
Q = 550. g × 2.03 J/g∙°C × 25.0°C
Q = 27982.5 J
Therefore, the heat needed to convert 550. g of wood from -15.0°C to 10.0°C is 27,982.5 J (joules).
To calculate the amount of heat needed to convert a given mass of wood from one temperature to another, you can use the equation:
q = m * c * ΔT
Where:
q is the heat energy required (in joules)
m is the mass of the wood (in grams)
c is the specific heat capacity of wood (in J/g∙°C)
ΔT is the change in temperature (in °C)
In this case:
m = 550 g
c = 2.03 J/g∙°C
ΔT = 10.0°C - (-15.0°C) = 25.0°C
Substituting the values into the equation:
q = 550 g * 2.03 J/g∙°C * 25.0°C
Now, let's calculate the answer:
q = 550 * 2.03 * 25
q ≈ 27,912.5
Therefore, approximately 27,912.5 joules of heat energy is needed to convert 550. g of wood from -15.0°C to 10.0°C.
heat it 25 deg C
550 * 2.03 * 25 Joules